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Homework Statement
"Estimate the highest possible frequency (in Hertz) and the smallest possible wavelength, of a sound wave in aluminium due to the discrete atomic structure of this material. The mass density, Young's modulus, and atomic weight of aluminium are 2.7x103kg m-3, 6x1010 N m-2, and 27 respectively.
Homework Equations
Second partial of Ψ(x,t) WRT t = second partial of Ψ(x,t) WRT x multiplied by (Young's modulus / mass density)
The Attempt at a Solution
Assuming the mode will follow the form
Ψ(x,t) = Acos(kx)cos(ωt - φ)
then the second partial WRT t will be
Ψ''(x,t) = -ω2Acos(kx)cos(ωt - φ)
and the second partial WRT x will be
Ψ''(x,t) = -k2Acos(kx)cos(ωt - φ)
Plugging into wave equation I get
-ω2Acos(kx)cos(ωt - φ) = -c2k2Acos(kx)cos(ωt - φ)
--> ω2 = κ2(Y/ρ)
--> ω = k(Y/ρ)1/2
--> 2\pi f = k(Y/ρ)1/2
--> f = \frac{k}{2\pi} \sqrt{\frac{Y}{\rho}}
Have no clue where to go from here. This may not even be the way to go about doing it. I guess I technically have the Young's modulus and mass density for the problem but I do not know how to calculate k, and don't understand how this system could vary in frequency to find the highest possible one. Any help would be appreciated, thanks. (Sorry, that I suck a latex btw)
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