What Is the Maximum Inclination for a Cylinder to Roll Without Slipping?

AI Thread Summary
The discussion revolves around determining the maximum angle at which a solid cylinder can roll without slipping on an inclined plane, given that a block of the same material begins to slide at 14.57°. Participants explore the relationship between friction, acceleration, and the moment of inertia, with one contributor calculating an unlikely angle of 89 degrees before correcting to 38 degrees. The consensus suggests that the maximum angle for the cylinder is indeed 14.57°, as friction does not depend on the shape of the object. The conversation highlights the importance of understanding the dynamics of rolling motion and the conditions for slipping.
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A block of a certain material begins to slide on an inclined plane when the plane is inclined to an angle of 14.57°. If a solid cyclinder is fashioned from the same material, what will be the maximum angle at which it will roll without slipping on the plane?

I really have no idea where to start on this problem since the only given is the angle. I know that the moment of inertia of a cylinder is (1/2)MR^2 if that's needed at all. Any hints?
 
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In what case does the cylinder slip (hint: friction)?
Another hint: total acceleration is the same as the tangential acceleration if there's no slipping.

(Would you happen to have the correct answer?)
 
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I'm having trouble with a similar problem.

I tried finding the coeff of friction; got an arctan14.7 ...

Then I set up the dynamics equations of the cylinder, taking the center of mass as the center of rotation; Wx - friction = ma

And then I put in no slipping condition i.e a = (angular acceleration) X R.

I substitude (angular acceleration) with the relevant expression using Newton's second law in angular form.

I solve and then I get a very unlikely value of 89 degrees. Where am I wrong.
 
Kenny Lee said:
I'm having trouble with a similar problem.
I tried finding the coeff of friction; got an arctan14.7 ...
According to my calculations you should get a plain tan (not arctan).

Then I set up the dynamics equations of the cylinder, taking the center of mass as the center of rotation; Wx - friction = ma
And then I put in no slipping condition i.e a = (angular acceleration) X R.
I substitude (angular acceleration) with the relevant expression using Newton's second law in angular form.
I solve and then I get a very unlikely value of 89 degrees. Where am I wrong.

The rest sounds, if I understood everything correctly, fine.
 
Oh right. Yea, tan 14.7 degrees. Thanks.
okay now i get 38 degrees... dat bout right?
 
I see how to do it now. Thank you
 
Kenny Lee said:
Oh right. Yea, tan 14.7 degrees. Thanks.
okay now i get 38 degrees... dat bout right?
If you mean the problem in this thread (with the angle actually being 14.57), I get the same answer.

Punchlinegirl said:
I see how to do it now. Thank you
No problem :smile:.
 
romured question

Punchlinegirl said:
A block of a certain material begins to slide on an inclined plane when the plane is inclined to an angle of 14.57°. If a solid cyclinder is fashioned from the same material, what will be the maximum angle at which it will roll without slipping on the plane?
I really have no idea where to start on this problem since the only given is the angle. I know that the moment of inertia of a cylinder is (1/2)MR^2 if that's needed at all. Any hints?
i think that it's a romured question in which the answer is 14.57 degree because friction doesn't pertain to shape of the block or how much is the surface of that
i think the answer is that
 
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