What Is the Maximum Load on an Incline for Equilibrium?

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To determine the maximum load on an incline for equilibrium, the discussion emphasizes analyzing the forces acting on the system, particularly the tension in the rope and the load G. The beam is considered weightless, and the friction coefficient is relevant only between the load and the incline. Participants suggest that the original poster should type out equations and provide detailed descriptions of their attempts to facilitate better assistance. Clear communication of the problem is crucial for effective help, especially when dealing with complex physics concepts. Overall, a structured approach to the problem is necessary for finding the solution.
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Homework Statement


[/B]
Determine the maximum load G [N] placed on the incline of an angle α, to ensure the
equilibrium of the system shown. The beam of length (a + b) is weightless and the
friction coefficient μ is only between the load G and the incline.

I have uploaded the question.
Untitled.jpg


Homework Equations

The Attempt at a Solution



I have tried to solve the question and am not able to solve further. Could anyone please help. I have uploaded the solution.
IMG_20150125_134950.jpg
 
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Hi mohdapadela, Welcome to Physics Forums.

I suggest that you start by analyzing the force P and lever ab to determine another expression for the tension in the rope. For the system to be in equilibrium the tension provided by lever must balance the tension produced by the load.

It would be preferable if you would type in your equations and provide some description of what you are trying to accomplish at each step. It is very difficult for helpers to comment on details of your work when it is in an image.
 
gneill said:
It would be preferable if you would type in your equations and provide some description of what you are trying to accomplish at each step. It is very difficult for helpers to comment on details of your work when it is in an image.

Especially blurry images which aren't rotated so you can read them. :mad:
 

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