What Is the Meteor's Altitude Due to Length Contraction?

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An observer on Earth measures a meteor at an altitude of 650m while it travels at 0.92c. To find the altitude as perceived by an alien on the meteor, one must apply the length contraction formula, where L = Lo/ɣ. The confusion arises from the assumption that both frames of reference are identical, but they are not; measurements of distance differ due to relativistic effects. The proper length (Lo) is the altitude measured by the Earth observer, while L is the contracted length perceived by the alien. Understanding the distinction between these frames is crucial for accurate calculations in relativistic physics.
debroglieman
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An observer on Earth sees a meteor approaching rapidly, heading directly for the Earth's surface. At a certain instant, the Earth observer sees the meteor at 650m altitude. If the meteor is traveling at 0.92c, as recorded by an Earth radar, what would be the altitude as measured by the alien resting on the meteor?



L=Lo (ɣ)



I know the solution is to plug in Lo = 650 and solve for L, but not know why this is so. It seems that the two inertial frames are identical, and as such the answer should be 650m? Advice/solution appreciated.
 
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No. The inertial frames are (not) identical (but symmetric), but measurements from them disagree anyway, such as those of distance. Remember that lengths appear* to change from frames of reference moving WRT the object whose length is being measured.

*for lack of better wording
 
Okay, so how do I know what is Lo and what is L?
 
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