What is the method for solving a steel pipe around a hallway?

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Homework Statement



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Homework Equations



Trigonometric identities and differentiation

The Attempt at a Solution



It's pretty simple to solve this question when the hallway is a right angle.

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Differentiating -6cscθ + 9secθ and setting it equal to zero and solving will yield the proper answer. But I don't know if the same method can be applied for this question? How would I start to solve this question?
 
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The same method can, but not using the same function obviously. Do you understand where the equation -6cscθ + 9secθ comes from geometrically? The same geometric argument can construct a function for this other hallway that you need to minimize
 
For the right-angle turn, you look at the part of the pipe in each hallway, and add them together. So cosθ = 9/L1 and -sinθ = 6/L2. You can make similar triangles in the hallway of question, but I don't think θ is can be used as the angle for both triangles. And how does the pi/4 play a part in this?
 
whoareyou said:
For the right-angle turn, you look at the part of the pipe in each hallway, and add them together. So cosθ = 9/L1 and -sinθ = 6/L2. You can make similar triangles in the hallway of question, but I don't think θ is can be used as the angle for both triangles. And how does the pi/4 play a part in this?

Let θ be the angle that the pipe makes with the 12 foot hallway's wall. You'll have to do a little geometry (not much, just tracking some angles) to find out what angle the pipe makes with the 8 foot hallway's wall, then set up a similar equation to calculate how long the pipe is. The fact that we have an extra pi/4 angle is just going to change what the relationship between the angle with the 12 foot wall and the angle with the 8 foot wall are related
 
So this is what I came up with,

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but the resulting theta values do not equate to the answer, which is 51.7762 ft.
 
Adding up all the angles on one half of the red line on the right should give me a total of \pi. But on the right half of the line you have
\pi/4 + \pi/4+\pi/4+\pi/4+\theta+\pi/2-\theta = 3\pi/2

So you have to double check those
 
Got it! It was θ - π/4 for the second triangle. Thanks :).
 
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