What Is the Minimum Force Required to Move the Box?

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To determine the minimum force required to move an 8 kg box that has come to rest due to friction, the kinetic friction force must first be calculated based on its initial speed of 11 m/s and the distance of 46 meters it traveled before stopping. The coefficient of kinetic friction can be derived from this information. Given that the coefficient of static friction is 1.21 times greater than the kinetic friction, this value is essential for calculating the force needed to overcome static friction. Ultimately, the minimum horizontal force in Newtons can be found by applying these friction coefficients to the box's weight. Understanding these relationships is crucial for solving the problem effectively.
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Homework Statement


A 8 kg box is initially traveling on a horizontal surface at a speed of 11 m/s and comes to rest after 46 meters due to the force of friction. If the coefficient of static friction is 1.21 times more than the coefficient of the kinetic friction, what is the minimum horizontal force needed in Newtons in order to move the box again?


Homework Equations


i drew out all my forces but not sure where to go from here


The Attempt at a Solution


All i found so fare was the Fn=78.48
 
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flsurfer said:

Homework Statement


A 8 kg box is initially traveling on a horizontal surface at a speed of 11 m/s and comes to rest after 46 meters due to the force of friction. If the coefficient of static friction is 1.21 times more than the coefficient of the kinetic friction, what is the minimum horizontal force needed in Newtons in order to move the box again?


Homework Equations


i drew out all my forces but not sure where to go from here


The Attempt at a Solution


Welcome to PF.

You need to first determine the force that the kinetic friction induced to slow it down.

Knowing that, you can determine the u of kinetic friction and then to figure the u of static friction that you can use to figure the force that needs to be overcome again.
 
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