What is the minimum image-object distance in a single lens system?

AI Thread Summary
In a single lens system, the minimum image-object distance must be greater than twice the focal length to create a real image. As the object distance decreases, the magnification increases until it reaches the focal plane, where no real image is formed. The relationship between image distance (i), object distance (o), and focal length (f) is described by the lens formula (1/f) = (1/i) + (1/o). To find the minimum distance, one can consider differentiating the equation, although it requires careful consideration of the variables involved. Ultimately, the system's symmetry suggests that the image distance equals the object distance at the minimum point.
kehler
Messages
103
Reaction score
0

Homework Statement


For a system with a single lens, what is the smallest image to object distance that you can achieve?

Homework Equations


I guess (1/f)=(1/i)+(1/o)


The Attempt at a Solution


Tried drawing a few ray diagrams but didn't seem to get anywhere :S
 
Physics news on Phys.org
Here's a clue:

"...a simple microscope, which consists of a single convex lens. Magnification is given by the ratio of the image distance, the distance between the lens and the image, and the object distance, the distance between the lens and the specimen. As the object distance decreases, the size of the magnified image increases proportionally. When the object distance reaches the focal plane of the lens, however, the rays exiting the lens emerge parallel, and no real image is created. In order to create a real image, the object distance must be greater than the focal length of the lens. A shorter focal length allows for a shorter distance between the object and the lens, and enables greater magnification."

http://laser.physics.sunysb.edu/~scott/liquid-lens/
 


Hm thanks. I guess that tells me it has to be greater than f, so the distance must be greater than 2f...
Is there any way to do it by differentiation? Cos that's how minimum values are usually found, right? I would try differentiating (1/f)=(1/i)+(1/o) but I don't know what I'm differentiating with respect to :S
 


You would write an equation for the total length ie, s=o+i in terms of 'o' or 'i' and f
I think you have to make the assumption that the system is symetric and so i=o.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
5
Views
1K
Replies
1
Views
2K
Replies
7
Views
3K
Replies
9
Views
2K
Replies
5
Views
2K
Replies
1
Views
1K
Replies
2
Views
1K
Replies
20
Views
4K
Back
Top