What Is the Minimum Mass Difference for Atwood's Machine with Friction?

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To determine the minimum mass difference required for an Atwood's machine with friction, the system must overcome a frictional force of 0.147 N. The total mass of the system is 250 g, and the acceleration can be calculated using the equation a = g(m/M) - f/M. The key is to ensure that one mass exerts a force greater than the other by at least 0.147 N to achieve non-zero acceleration. Plugging in the values into the equation helps find the necessary mass difference. Understanding the relationship between mass, tension, and friction is crucial for solving the problem.
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Homework Statement



Two masses are connected over a pulley which has a friction resistance of 0.147 N. What is the minimum mass difference to cause the pulley system to have a non-zero acceleration when released from rest? Total Mass = 250 g

Homework Equations



a= g[(m))/((M)]- f/((M)) Or

a= g[(m))/((M)]

m = mass difference
M = Total mass

The Attempt at a Solution



I just need to get started off in the right direction, as i don't really understand the question
 
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One side must pull down on the pulley with a force that is 0.147 N greater than the other. Hint: How does the weight of masses relate to the tension in the rope?
 
Can i just plug in all the values in the equation a= g[(m))/((M)]- f/((M)), and a = 0 and solve for m?
 

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