What is the moment of inertia of the particle at the end of the meter stick?

AI Thread Summary
The discussion focuses on calculating the moment of inertia of a particle attached to a meter stick. The particle has a mass of 0.400 kg and is located at the 100-cm mark of a meter stick weighing 0.100 kg. The moment of inertia for the particle is determined using the formula I = mr², where 'm' is the mass and 'r' is the distance from the pivot point. The calculations involve two pivot points: one at the 50.0-cm mark and another at the 0-cm mark. The thread emphasizes the importance of understanding both the particle's and the meter stick's contributions to the system's overall moment of inertia.
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Moment of Inertia

A particle of mass 0.400 kg is attached to the 100-cm mark of a meter stick of mass 0.100 kg. The meter stick rotates on a horizontal, frictionless table with an angular speed of 4.00 rad/s. Calculate the angular momentum of the system when the stick is pivoted about an axis (a) perpendicular to the table through the 50.0-cm mark and (b) perpendicular to the table through the 0-cm mark.

What is the moment of intertia of the particle at the end of the meter stick? I know how to find the moment of intertia of the meter stick.
 
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The moment of inertia of a particle is mr^2
 
thank you
 

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