What is the Motional EMF in a Solenoid with a Square Loop Inside?

AI Thread Summary
The discussion focuses on calculating the magnetic flux through a square loop placed inside a solenoid and determining the average induced electromotive force (emf) when the current in the solenoid is reduced to zero. The magnetic field inside the solenoid is correctly identified using the formula B = (μ₀ * I * N) / l, yielding a value of 0.00224 T. The participants emphasize the importance of calculating the flux through the square loop specifically, rather than the solenoid's area. After some initial confusion, the user resolves their mathematical errors and successfully computes the required values. The conversation highlights the significance of understanding the orientation of the loop in relation to the magnetic field for accurate calculations.
goWlfpack
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Homework Statement



A square, single-turn wire loop 1.00 cm on a side is placed inside a solenoid that has a circular cross section of radius 3.00 cm, as shown in the figure below. The solenoid is 16.0 cm long and wound with 95 turns of wire.

(a) If the current in the solenoid is 3.00 A, find the flux through the loop.
T · m2

(b) If the current in the solenoid is reduced to zero in 4.00 s, find the magnitude of the average induced emf in the loop.
V



Homework Equations



EMF=-N mflux/delta t

where N is the number of turns

The Attempt at a Solution


im just having trouble manipulating the equation to get my unknowns...
 
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First things first: What's the field inside the solenoid?
 
given as B=constant(current)/2R
radius is 3 so
6.3e-7?
 
You'd better look up the formula for the field within a solenoid.
 
Doc Al said:
You'd better look up the formula for the field within a solenoid.

ok i found the magnetic field inside the solenoid. it is B=(Moconstant)(I)(N/l)
where N is the number of turns and l is the length
this comes to .00224
so then i tried to multiply it by the area of the soleniod and i got the wrong answer.
so i tried it multiplied by the area of the square loop inside the soleniod and that was also a red x...
any help?
 
goWlfpack said:
ok i found the magnetic field inside the solenoid. it is B=(Moconstant)(I)(N/l)
where N is the number of turns and l is the length
this comes to .00224
Looks OK.
so then i tried to multiply it by the area of the soleniod and i got the wrong answer.
That was a mistake, since you need the flux through the square loop.
so i tried it multiplied by the area of the square loop inside the soleniod and that was also a red x...
That should work. Is the loop oriented perpendicular to the field or is it at some other angle? What did you use for the area of the loop?
 
Doc Al said:
Looks OK.

That was a mistake, since you need the flux through the square loop.

That should work. Is the loop oriented perpendicular to the field or is it at some other angle? What did you use for the area of the loop?

yea sorry minor mathmatical error. I got it now! thanks for all the help! :)
 
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