What is the natural force of a 25kg block that is not moving?

AI Thread Summary
The discussion centers on calculating the natural force acting on a stationary 25kg block using the formula F=ma, where g is the acceleration due to gravity at 9.81 m/s². The calculation yields a force of 245.25 N, which is confirmed as correct. Participants clarify that the unit of force in the SI system is Newtons, not kilograms. The conversation emphasizes understanding the proper units and the application of the formula in this context. Overall, the natural force of the block is determined to be 245.25 N.
Angieesaurus
Messages
2
Reaction score
0
What is the natural force of a 25kg block that is not moving?F=ma, g=9.81m/s^2

Attempt:
(25kg)*(9.81m/s^2)= 245.25kg ?
 
Physics news on Phys.org
Angieesaurus said:
What is the natural force of a 25kg block that is not moving?F=ma, g=9.81m/s^2

Attempt:
(25kg)*(9.81m/s^2)= 245.25kg ?
Looks OK to me. Is there any information you left out?

BTW, don't delete the three template parts. I can see that you used the template, but leave the template headings in when you start a new thread.
 
Natural force? What does it mean?
 
Angieesaurus said:
What is the natural force of a 25kg block that is not moving?F=ma, g=9.81m/s^2

Attempt:
(25kg)*(9.81m/s^2)= 245.25kg ?

kg * m/s^2 = kg? I don't think so. What is the unit of force in the SI system?
 
SteamKing said:
kg * m/s^2 = kg? I don't think so. What is the unit of force in the SI system?
Newtons?
 
Yes.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Concrete Block Incline acceleration question
Replies
4
Views
1K
Frictional Force Problem: Solve with 25kg & 0.36 Coefficient
Replies
6
Views
1K
How Do You Calculate the Angle of a Slipping Ladder?
Replies
1
Views
1K
Force pulling on a string at an angle with a block at the other end
Replies
2
Views
1K
How can I determine the instant the block overcomes static friction?
2
Replies
61
Views
3K
How to find the minimum horizontal force?
Replies
11
Views
20K
Calculating Force and Momentum: A Catcher's Challenge
Replies
4
Views
2K
Dynamics of a Block on top of a slab with friction between them
Replies
33
Views
1K
Newton's law problem: Pushing 2 stacked blocks on a horizontal table
Replies
13
Views
3K
Pseudo Forces on a Mass in a Groove on a Rotating Disc
Replies
5
Views
760

Hot Threads

Recent Insights

Back
Top