What is the Net Force on an Angled Surface in a Limited Force Scenario?

Click For Summary
SUMMARY

The net force acting on an angled surface in a limited force scenario is determined by the pressure applied to the external surface only, not the internal surfaces. If pressure is acting on all surfaces, the net force will be zero, indicating equilibrium. For the specific case of a 45-degree angled surface, the net force is calculated using the frontal area or projected area multiplied by the pressure applied. The engineer's assertion that the force is X parallel to the centerline is incorrect; the correct calculation involves the cosine of the angle, resulting in a force of [cos(45)*X].

PREREQUISITES
  • Understanding of basic physics concepts, particularly force and pressure.
  • Familiarity with vector decomposition in physics.
  • Knowledge of equilibrium conditions in mechanical systems.
  • Ability to interpret and analyze diagrams related to force applications.
NEXT STEPS
  • Study vector decomposition in physics to understand force resolution.
  • Research the concept of projected area in fluid mechanics.
  • Learn about equilibrium conditions in mechanical systems.
  • Explore practical applications of pressure forces in engineering design.
USEFUL FOR

Mechanical engineers, physics students, and professionals involved in design and analysis of pressure systems will benefit from this discussion.

rush02112
Messages
2
Reaction score
0
I prepared a drawing to reference what i am trying to explain:

http://i20.photobucket.com/albums/b225/rush02112/part1.jpg

I will have pressure acting against the all surfaces of this part. Notice this part will only be able to move parallel to the center line of the part. I want to know if the net force acting against the 45 degree angle will be X in parallel direction of the centerline or if it is [cos(45)*X]

I was told by the engineer i work with that the angled surface will be pushed with force X parallel to the centerline. This is why i ask since that doesn't make sense to me. I would think that the force would act on the angled surface perpendicular to which the resulting force would be [(cos(45)*x]
 
Last edited by a moderator:
Physics news on Phys.org
rush02112 said:
I prepared a drawing to reference what i am trying to explain:

http://i20.photobucket.com/albums/b225/rush02112/part1.jpg

I will have pressure acting against the all surfaces of this part. Notice this part will only be able to move parallel to the center line of the part. I want to know if the net force acting against the 45 degree angle will be X in parallel direction of the centerline or if it is [cos(45)*X]

I was told by the engineer i work with that the angled surface will be pushed with force X parallel to the centerline. This is why i ask since that doesn't make sense to me. I would think that the force would act on the angled surface perpendicular to which the resulting force would be [(cos(45)*x]

If you really mean that you have a pressure acting on all of the surfaces, internal and external, then the net force will be zero and the part will be in equilibrium.

If you mean that you have pressure acting on the external surface only, then the net force is given by the "frontal area" or "projected area" multiplied by the pressure. This area is the area you see if you look at the part from the end.
 
Last edited by a moderator:
Im just concerned about the 1 external angled surface at the moment. When this part is assembled in the tool, only a limited number of surfaces will see the force described. I wanted to try and keep the drawing and description as simple as possible
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 20 ·
Replies
20
Views
5K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 77 ·
3
Replies
77
Views
6K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K