What is the Net Traction Force on a Pulley in a Traction System?

AI Thread Summary
The discussion revolves around calculating the net traction force on a pulley system used for a patient in traction. The tension in the rope, resulting from a 6 kg hanging mass, is confirmed to be 58.8 N, but participants express confusion about how this tension interacts with angles and the pulley system. To solve for the net traction force, the vertical and horizontal components of the tension must be resolved, particularly considering the angle of the upper rope. Participants are encouraged to analyze the forces acting on the boot to determine the necessary components to maintain equilibrium. Overall, understanding the relationship between tension, angles, and force components is crucial for solving the problem.
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1. Homework Statement
pg14733.jpg

Can you see the picture?
"An accident victim with a broken leg is being placed in traction. The patient wears a special boot with a pulley attached to the sole. The foot and boot together have a mass of 4 kg, and the octor has decided to hang a 6 kg mass from the rope. The boot is held suspended by the ropes and does not touch the bed.

a) Determine the amount of tension in the rope by using Newton's laws to analyze the hanging mass.
b) The net traction force needs to pull straight out on the leg. What is the proper angle (theta) for the upper rope?
c. what is the net traction force pulling on the leg?
hint: if the pulleys are frictionless, which we will assume, the tension in the rope is constant from one end to the other"

2. Homework Equations
F= ma

3. The Attempt at a Solution
The 6kg hanging mass is pulling on the rope with 58.8 N right? but then how does the pulley and angles affect everything? the answer to A is 58.8 N right? Is that tension the same in all parts of the rope? That's what the hint is telling us right?
For b and c, i don't even understand what it's asking. What's a net traction force?
so since we know the tension of the string is 58.8 N, that means that the hypotenuse to the triangle with the 15 degree angle is 58.8 too right? The hypotenuse being the length of rope between the two pullies?

From that can we say the lengths of the sides of that triangle is 58.8sin15 (15.219) and 58.8cos15(65.796)? but then what do you do with that information? I still don't get b & c
 
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You are correct in almost everything, except the fact that the 58.8 doesn't represent the length of the string, it represents the magnitude of the tension force acting through the rope.

The next step would be to analyse the forcing acting on the boot, resolving them into their vertical and horizontal components.
 
I too am working on this problem and can't get past part A.

I have no clue what to do on the angle part.

I know the Fnet(y) should be zero since the boot is pulling straight out, but I can't get any further than that...
I also imagine somehow that i will find acceleration along the x-axis, then because the system is in equilibrium (the leg will not move), I will use acceleration and the mass of the boot to find the net traction force.

Can someone lend a hand?
 
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Anyone get any further/solve this problem?

Working on it now, and am pretty stuck trying to figure out parts b and c.

any help would be appreciated
 
jdm08151 said:
Anyone get any further/solve this problem?

Working on it now, and am pretty stuck trying to figure out parts b and c.

any help would be appreciated


shameless bump? anybody get any further on this?
 
Write out the vertical components of the tension in both ropes. You have to use the angles. What should be the resultant of these components to overcome the weight of the boot?

ehild
 
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