What is the new separation between the charges?

AI Thread Summary
The discussion focuses on calculating the new separation distance between two positive point charges after their electric potential energy doubles. The initial separation is 0.86 m, and the potential energy formula used is PE = kQ_aQ_b/d. By simplifying the equation and canceling common terms, the new distance is derived as d = 0.43 m. The calculation confirms that the new separation is correct. The solution demonstrates the application of electric potential energy principles in determining charge separation.
kdrobey
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Homework Statement




Two positive point charges are held in place, 0.86 m apart. They are then moved so that their electric potential energy doubles. What is the new separation between the charges?

Homework Equations



kq/r

The Attempt at a Solution


had PEb=KQaQb/d=2EPEa, then did KQaQb/d=2(KQaQb/.86. but cannot figure out how to solve it further
 
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kdrobey said:
... then did KQaQb/d=2(KQaQb/.86.
This is good. Simply and solve for d. Start by canceling everything that can be canceled from both sides of the equation.
 
both sides of the equation had KQaQb, i canceled the part out on both sides, leaving, 1/d=2(1/.86). then 1=2.32d. d=.43?
 
Looks good to me.
 
awesome, thanks
 
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