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**A 10,500kg railroad car travels alone on a level, frictionless track with a constant speed of 15.0 m/s. An additional 5,000kg load is dropped from a tower onto the car. What will then be its new speed?**

**2. Homework Equations**

Momentum of conservation: m1i+m2i=(m1+m2)vf

Momentum of conservation: m1i+m2i=(m1+m2)vf

**3. The Attempt at a Solution**

Plugging in the numbers i get:

10,500kg(15m/s) + 0 = (10,500 kg+5000 kg)vf

157500kgm/s+0=(15,500kg)vf

10.16 m/s=vf

vf=10.2m/s

is this correct?

Plugging in the numbers i get:

10,500kg(15m/s) + 0 = (10,500 kg+5000 kg)vf

157500kgm/s+0=(15,500kg)vf

10.16 m/s=vf

vf=10.2m/s

is this correct?