What Is the Normal Force Acting on a Box Pulled by a Mule?

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The discussion centers on calculating the normal force acting on a box being pulled by a mule across a level surface. The box weighs 3.0 x 10^2 Newtons, and the tension in the rope is 1.0 x 10^2 Newtons, with the rope angled at 30 degrees above the horizontal. The normal force can be determined by considering the weight of the box and the vertical component of the tension force. Understanding the tension force as the force transmitted through the rope is crucial for solving the problem. The normal force is essential for analyzing the forces acting on the box in this scenario.
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A mule uses a rope to pull a box that weighs 3.0 times ten to the second Newtons across a level surface with constant velocity. The rope makes an angle of thirty degrees above the horizontal, and the tension in the rope is one times ten squared Newtons. What is the normal force of the floor on the box?

I think I know how to do this problem but the main problem is that I don's know what a tension force is.
 
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The tension force is the force transferred through the rope
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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