What is the null space of TΦ for Φ = x over the interval [0,1]?

  • Thread starter Thread starter tavi
  • Start date Start date
  • Tags Tags
    Null space Space
tavi
Messages
1
Reaction score
0
Let V denote the vectore space of continuously differentiable functions, ƒ, over the interval [0,1] such that ƒ(0)=0.
Suppose Φ is-contained C∞ [0,1] (set of infinitely differentiable functions over the interval [0,1]) and define the operator
TΦ:V→R:ƒ→∫ƒ'(x)Φ(x)dx 0,1
Describe the null space of TΦ if Φ = x (Hint: integration by parts)
 
Physics news on Phys.org
Please dont' multiple post.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top