What is the output speed at 100 rpm arm rotation in an epicyclic gear box?

AI Thread Summary
The discussion centers on understanding the output speed of an epicyclic gearbox when the arm rotates at 100 rpm. It clarifies that the output shaft is connected to the second sun gear (S2), while the arm connects the planetary gears. When the arm is stationary at 0 rpm, a standard reduction occurs between the input and output. At 300 rpm, the system locks, resulting in the output shaft also rotating at 300 rpm. Therefore, the output speed at 100 rpm of the arm can be estimated to be one-third between the output at 0 rpm and 300 rpm.
gtbiyb
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Hi,
Cant understand this at all, even modeled the set up with lego but still can't fathom it! I can't see how the arm can rotate with locking something.

Cheers
 

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hi, The diagram is a bit misleading. the output shaft is attached to the second sun gear S2. input is S1, the arm just connects the planetary gears (P1 and P2). Just think about it this way. If you have the arm at 0 rpm, you have just a standard reduction between the input and output right? that's easy to work out, let's call that output X. Now, if you have the arm at 300 rpm, matching the speed of the input, the system will be locked, and the output shaft will be at 300 rpm. extrapolate what you find between these two points to find the output at 100rpm.

Again,
the output will basically lie 1/3rd between the X (arm = 0 rpm) and 300rpm (arm = 300rpm)
 

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