SUMMARY
A sound source emitting 80dB at a distance of 30 meters has a calculated power output of 1.13 watts. This conclusion is derived using the formula for sound intensity, where 80dB corresponds to an intensity of 10^(-4) W/m². The power is determined by the equation P = I * A, with A being the surface area of a sphere (4πr²) at the given distance. Despite the calculated power, the answer does not match the provided options, indicating a possible error in the question's answer choices.
PREREQUISITES
- Understanding of sound intensity and decibels (dB)
- Familiarity with the formula for sound intensity: I = P/A
- Knowledge of the reference intensity level Io = 10^(-12) W/m²
- Basic geometry of spheres for calculating surface area
NEXT STEPS
- Study the relationship between sound intensity and decibel levels in detail
- Explore the derivation of sound power calculations from intensity
- Investigate common errors in sound-related exam questions
- Learn about the implications of sound dispersion in different environments
USEFUL FOR
Students preparing for physics exams, educators teaching acoustics, and anyone interested in the practical applications of sound intensity calculations.