What Is the Power of a Sound Source Emitting 80dB at 30m?

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A sound source emits 80dB at a distance of 30m, which corresponds to an intensity of 10^(-4) W/m^2. The power of the source can be calculated using the formula P = I * A, where A is the surface area of a sphere (4πr^2). Substituting the values, the calculated power is approximately 1.13W. This result does not match the provided answer choices, leading to confusion among participants. The discussion highlights the challenges faced in accurately interpreting exam questions and answers.
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Homework Statement



A sound source emits uniformly in all directions. It produces a sound level of 80dB at a distance 30m. What is the power of the emitting source. (W)

Homework Equations



dB = 10log(I/Io)

Io = 10^(-12) W/m^2

I = P/A


The Attempt at a Solution



80dB = 10^(-4) W/m^2

sound disperses in a sphere..

I = P/(4*pi*r^2)

P = 10^(-4)*4*pi*(30)^2

= 1.13W


This answer is not listed, although multiples of it, 2.26, 3.39, 4.52 are choices.
 
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oo well, I think you did it right. I also get same thing =P
See the answers carefully , you will notice that a) is 13 and things on left side are erased, so it must be 1. on the left!

Anyways, good luck with the exam tomorrow!

P.S. funny how I also got stuck on the same question.
 
ah i see it. I found it odd that I was getting a wrong answer for the easiest question on the exam. thought maybe Rohan was playing tricks on me.

yeah good luck yourself (seems to be a good share of waterloo students here), no more bell curve anymore to take away the wrong answers!
 
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