What is the Power Series for exp(z) + exp(w*z) + exp(z*w^2)?

gertrudethegr
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We have already shown 1+ w+ w^2 =0

If w is the complex number exp(2*Pi*i/3) , find the power series for;
exp(z) +exp(w*z) + exp (z*w^2)

We have already shown 1+ w+ w^2 =0
 
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If 1+w+w^2=0, can you tell me what are w^3, w^4, w^5 ...? Now do a power series expansion of the exponentials and combine like powers of z. Do you see a pattern?
 
Thanks!

So w^3=1
w^4= w^1
w^5=w^2 etc

so
exp(z) +exp(w*z) + exp (z*w^2)= 3 + 0 +0 + 3*z^3/3! + 0 + 0 +3*z^6/6! etc,

But where do i go from here?
Thankyou for your time
 
gertrudethegr said:
Thanks!

So w^3=1
w^4= w^1
w^5=w^2 etc

so
exp(z) +exp(w*z) + exp (z*w^2)= 3 + 0 +0 + 3*z^3/3! + 0 + 0 +3*z^6/6! etc,

But where do i go from here?
Thankyou for your time

You are done, aren't you? The problem asked for a simple form of the power series, and you just showed it to me.
 
That is a valid point!

Thanks dick
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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