What Is the Pressure Difference When Wind Speed Is 6 m/s?

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SUMMARY

The pressure difference when the wind speed is 6 m/s is calculated to be 3.21 N/m² using Bernoulli's equation. The equation considers the velocity of air flow above a flat surface, where the speed of air is noted as 1.07 times the velocity (Vo). The discussion emphasizes the application of Bernoulli's principle in determining pressure differences in fluid dynamics.

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Apprentice123
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Admit Wed to speed the flow of air above the rear door of the cave is equal to 1,07Vo. Calculate the pressure difference p(1) - p(2) when the wind speed in the flat surface is equal to 6 m/s.

Answer:
3,21 N/m^2

figure:
http://www.physicshelpforum.com/physics-help/attachments/advanced-mechanics/434d1253986504-pressure-3.14.jpg
 
Last edited by a moderator:
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Apprentice123 said:
Admit Wed to speed the flow of air above the rear door of the cave is equal to 1,07Vo. Calculate the pressure difference p(1) - p(2) when the wind speed in the flat surface is equal to 6 m/s.

Answer:
3,21 N/m^2

figure:
http://www.physicshelpforum.com/physics-help/attachments/advanced-mechanics/434d1253986504-pressure-3.14.jpg

My attempt:

Bernoulli:

Z1 + P1/y + V1^2/2g = Z2 + P2/y + V2^2/2g

I have:
V1 and V2. But I do not have Z1 and Z2
 
Last edited by a moderator:

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