What is the pressure needed to sedate a dog in 1 second?

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Jane, a vet, needs to determine the pressure required to inject 3 ml of anesthetic into a dog within one second using a syringe with specific dimensions and fluid viscosity. The discussion revolves around applying Poiseuille's equation to calculate the necessary pressure, with participants clarifying the conversion of units and the relationship between diameter and radius. There is confusion over the calculations, particularly regarding the values substituted into the equations, leading to an unusually high pressure result. Participants emphasize the importance of correctly interpreting the internal diameter and ensuring proper unit conversions. The conversation highlights the challenges of applying fluid dynamics principles in a practical veterinary context.
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Homework Statement


Jane, a vet, is trying to sedate a dog by injecting him with sedative in a hypodermic syringe that
has a needle 20mm long with internal diameter 0.4 mm. The vet wishes to inject the dog with
3 ml of anaesthetic that has viscosity 4 x10^-3 Pas. Since the dog is struggling hard, she needs
to get it into his bloodstream within 1 second.
(a) How much pressure needs to be applied to the fluid in the syringe barrel to achieve this
rate of flow through the needle?
(b) Explain why this is pressure is not absolute, but is relative to atmospheric pressure.
(c) If the barrel of the syringe is 10mm in diameter, what force does Jane need to apply to the
plunger to achieve the needed flow rate

Homework Equations


Poiseullie or Bernouli

The Attempt at a Solution


Hi there, I'm stuck at this question. I don't know if I should use pensoulli's equation or bernoulis! Well the question did ask how much pressure, but idk how to tackle this question :( I'm seeking advise please[/B]
 
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Are you looking for flow rate? Or, energy conservation? Which equation applies?
 
Flow rate I think. But again it asked for pressure also so i don't know where to start with.
 
Derek1997 said:
Flow rate
Which equation depends on ΔP?
 
Bystander said:
Which equation depends on ΔP?
heres what I think, so Q is flow rate right? can we do 3ml/1= 3ml/s? then sub the value inside the it into the poiseulles equation?
 
Yup.
 
Bystander said:
Yup.
is it actually?
 
It is; you'll have to convert/invert between CGS & MKS units (ml, Pa⋅s, mm, and so on).
 
alright, so here's what I've done=
delta p= 8*u*L.Q/pi*r^4
where I got my Q as 3m/s
I converted my Length into 0.02m
R= 0.0004m
Then i subbed the value inside equation as = 8.4x10^-3pa x 0.02m x 3m/s / pi x 0.0004^4= 2.38x10^10pa which looks weird!
 
  • #10
Derek1997 said:
internal diameter 0.4 mm
Derek1997 said:
Q as 3m/s
That looks high to me; can you double check it?
 
  • #11
I did but still yeilds me the same, although I'm not sure about one thing.. for r i used "internal diamater 0.4mm" which i converted to meters?
 
  • #12
Derek1997 said:
R= 0.0004m
Derek1997 said:
diamater 0.4mm"
Does radius equal diameter?
Derek1997 said:
viscosity 4 x10^-3 Pas
Not 8.4 ... :H
Derek1997 said:
3 ml
One milliliter is 10-6 m3.
 
  • #13
Bystander said:
Does radius equal diameter?

Not 8.4 ... :H
One milliliter is 10-6 m3.
haha I didn't do 8.4 it was type mistake, also in regard to radius, we are not given how am I suppose to find it?
 
  • #14
Half the diameter?
 
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  • #15
Thanks mate, I gave you a life :) p.s if u had time check out my other question as well. Thanks
 
  • #16
Derek1997 said:
Thanks mate, I gave you a life :) p.s if u had time check out my other question as well. Thanks
like* haha
 
  • #17
All nighter?
 
  • #18
Nein, I am finished with my chem so I am about to sleep haha
 
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