What Is the Pressure of Methyl Cyanide After 520 Seconds?

AI Thread Summary
The discussion centers on calculating the pressure of methyl cyanide after 520 seconds of a first-order reaction involving methyl isocyanide isomerizing to methyl cyanide. The rate constant for the reaction is given as 7.70x10^-4 s^-1 at 500K, with an initial pressure of 25.0 torr. The user initially calculated the pressure of methyl cyanide as 16.75 torr but found a discrepancy with the book's answer of 8.25 torr. Clarification is sought on whether the user mistakenly calculated the pressure for methyl isocyanide instead. The focus remains on resolving the calculation error to determine the correct pressure of methyl cyanide.
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Homework Statement


In the gas phase methyl isocyanide (CH3NC) isomerizes to methyl cyanide (CH3CN) in a first order reaction with a rate constant of 7.70x10^-4s^-1 at 500K. An experiment is performed, where 25.0 torr of methyl isocyanide is placed in 23.2L container at 500K.

After 520 seconds, what is the pressure of methyl cyanide?


Homework Equations


ln (P)t/(P)0 = -kt


The Attempt at a Solution


I used the equation above to solve for (P)t, and I got 16.75, but the answer in my book is 8.25 torr, what am I doing wrong here? Please help...
 
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