What Is the Probability Juliet Replies on Tuesday If She Hasn't on Monday?

brandy
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Homework Statement


romeo proposed to juliet. now he's waiting for her response.
R = 'event that she replies'
W='event that she wants to get married'
Mon = 'event on monday'
Tue = 'event on Tuesday'

P(R\wedgeMon | W) = 0.2
P(R\wedgeTue | W) = 0.25
P(R\wedgeMon| \bar{W}) = 0.05
P(R\wedgeTue | \bar{W}) = 0.1
P(R|W) = 1.0
P(R|\bar{W}) = 0.7
P(W)=0.6

If Romeo has not received her reply on Monday, what is the probability that he will receive the letter on Tuesday?

Homework Equations


there are more probabilities for each day of the week for both W and bar W.


The Attempt at a Solution



I used to total probability to calculate P(R \wedge Mon) = 0.25, and for tuesday = 0.35
and i believe what I am trying to calculate now is P(R\wedge Tue | \bar{Mon}) \wedge W)

so far, because its too difficult to latex it all. i have applied bayes theorem, and i have tried fiddling around with all 4 of the given ones. I need some direction.
 
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brandy said:

Homework Statement


romeo proposed to juliet. now he's waiting for her response.
R = 'event that she replies'
W='event that she wants to get married'
Mon = 'event on monday'
Tue = 'event on Tuesday'

P(R\wedgeMon | W) = 0.2
P(R\wedgeTue | W) = 0.25
P(R\wedgeMon| \bar{W}) = 0.05
P(R\wedgeTue | \bar{W}) = 0.1
P(R|W) = 1.0
P(R|\bar{W}) = 0.7
P(W)=0.6

If Romeo has not received her reply on Monday, what is the probability that he will receive the letter on Tuesday?

Homework Equations


there are more probabilities for each day of the week for both W and bar W.


The Attempt at a Solution



I used to total probability to calculate P(R \wedge Mon) = 0.25, and for tuesday = 0.35
and i believe what I am trying to calculate now is P(R\wedge Tue | \bar{Mon}) \wedge W)

so far, because its too difficult to latex it all. i have applied bayes theorem, and i have tried fiddling around with all 4 of the given ones. I need some direction.

What formulas did you use to get P{Mon & R} = 0.25, etc.? I get very different results.

RGV
 
i just did P(R∧Mon | W) + P(R∧Mon| Wˉ) = 0.2+0.05=0.25
so, this isn't right?
 
brandy said:
i just did P(R∧Mon | W) + P(R∧Mon| Wˉ) = 0.2+0.05=0.25
so, this isn't right?

No. Go back and look in detail at Bayes' Theorem.

RGV
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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