What Is the Quantum State |l,m> After Angular Momentum Measurement?

atomicpedals
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Homework Statement



The square angular momentum L2 and the z-component Lz of a free particle are measured. They are found to be L2=6\hbar^2 and Lz=\hbar

What is the state |l,m> of the system after measurement?

Homework Equations



L2|l,m>=\hbar^2l|l,m>
Lz|l,m>=\hbarm|l,m>

The Attempt at a Solution



Is this simply:

L2|lm>=\hbar^2l|l,m>=6\hbar^2|6,m>
Lz|l,m>=\hbarm|l,m>=\hbar|l,1>

|l,m> = |6,1> ?
 
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I'm getting some contradiction from my notes, the other way I see it the eigenstates could be |2,1>.
 
It's \vert 2 ~ 1 \rangle. Your first "relevant equation" is incorrect.
 
Cool, means page two of my notes needs a quick correction. Thanks!
 
As a follow up to see if I'm slowly catching on; would the expectation value for Lx then be given by <lm|Lx|lm>?
 
Yes.
 
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