What is the rate of change of amplitude for standing waves with respect to x?

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Differentiating the standing wave equation y=Asinkxcosωt with respect to x provides the slope of the wave at a given instant, represented as dy/dx=Akcos(kx). Setting t=0 gives a snapshot of the wave where all particles are at their maximum amplitudes. The discussion clarifies that the rate of change of amplitude along the x-axis can be interpreted as the velocity of the particles in the wave. Thus, the derivative indicates how amplitude changes as one moves along the x-axis. This understanding is essential for analyzing wave behavior in oscillating strings.
nil1996
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Equation of standing waves→ y=Asinkxcosωt

What do i get if i differentiate the above equation with respect to "x" ?
Do i get the rate of change of amplitude when i put t=0?
 
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when you differentiate it with respect to x, then you get slope of the curve/wave at a given instant ##\frac{dy}{dx}=slope##.
 
rate of change of amplitude is velocity, ##\frac{dy}{dt}=##velocity of particle
 
Lets consider a string oscillating in fundamental frequency. In the wave equation if i put t=0 the i will get a snapshot of the wave in which all particles will be at their amplitudes. Now if i differentiate the equation that is y=Asinkx i will get something like \frac{dy}{dx}=Akcoskx and i think this will be the rate of change of amplitude on the string. Isn't it right?
 
NihalSh said:
rate of change of amplitude is velocity, ##\frac{dy}{dt}=##velocity of particle

I want to say how much the amplitude changes as i move forward on x-axis.
 
nil1996 said:
I want to say how much the amplitude changes as i move forward on x-axis.

Yes, you can say that!
 
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