What is the relationship between A_{c} and A_{s} in simple harmonic motion?

AI Thread Summary
The discussion focuses on deriving the relationship between the amplitudes A_{c} and A_{s} in simple harmonic motion from the equation A_{0}cos(ωt + δ). It emphasizes using trigonometric identities to express the equation in terms of sine and cosine components. The initial position of the particle is linked to A_{c}, while the initial velocity relates to A_{s}. The confusion arises around the necessity of taking derivatives to find these relationships. Understanding these connections is crucial for solving problems related to simple harmonic motion.
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1. Homework Statement
(a) Show that A_{0}cos(\omegat+\delta) can be written as A_{s}sin(\omegat)+A_{c}cos(\omegat), and determine A_{s} and A_{c} in terms of A_{0} and \delta.
(b) Relate A_{c} and A_{s} to the initial position and velocity of a particle undergoing simple harmonic motion.




2. Homework Equations
x=Acos(\omegat+\delta)
v_{<i>x</i>}=-\omegaAsin(\omegat+\delta)




3. The Attempt at a Solution
I have absolutely no idea where to begin...please help! Thanks a bunch for whoever does!

 
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Start with the trigonometric identity for cosine of the sum of two angles, e.g. cos (a+b) = cos a cos b - sin a sin b, and see where that leads.

The initial position and velocity are taken at t = t0 or t = 0?
 
I got the first part by using the trig identity and then taking the derivative, except I don't know why I had to take the derivative but it worked out anyway so I did.
Now, if t=0 then that would make the sine portion of the position 0 and the cosine portion 1 so the initial position would equal Ac, right?
For velocity, what would I do with that or is my whole idea wrong?
 
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