What is the relationship between phi(r,t) and the given wave functions?

Lee
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Homework Statement


phi(r,0)=1/rt(2)(phi1+ph2)

What is phi(r,t)?

Homework Equations


The Attempt at a Solution



Is this simply a case of introducing a phase constant to the eqn. So:

phi(r,t)=1/rt(2)(phi1+phi2)e^i(theta)t

or do we need to modify phi1 and phi2.
 
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phi1 exp(-iE_1 t/hbar)+ same for 2.
 
Oh, sorry.

phi1=Aexp(-r/ao)
phi2=B(1-r/ao)e(-r/2ao)

where ao is the Bohr radius.

As given by the question.

So can I take the Energy of each wave function (that I have already calculated) and apply the above substitution?
 
Can any give me some clarification.
 
Lee said:
Oh, sorry.

phi1=Aexp(-r/ao)
phi2=B(1-r/ao)e(-r/2ao)

where ao is the Bohr radius.

As given by the question.

So can I take the Energy of each wave function (that I have already calculated) and apply the above substitution?
Yes, just multiply each phi by exp{-iEt/hbar} and add.
 
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