What is the relationship between stopping potential and the intensity of light?

[tnecniv]

The higher the intensity of the light we will get a higher stopping potential.
Why is that so? is there any theory and formula to justifiy this behavior?

How is wavelength affecting the intensity of light?

Please advise.

Thank You

 

[Fightfish]

Are you sure a higher intensity of light leads to a higher stopping potential? That is contrary to the photoelectric effect!
The wavelength and intensity of light are independent properties.

 

[beakspyder]

Are you sure a higher intensity of light leads to a higher stopping potential? That is contrary to the photoelectric effect!
The wavelength and intensity of light are independent properties.

Well, theoretically it doesn't. I just did and experiment on this my result shows that when the intensity of light reduces, the stopping potential, albeilt slightly, reduces as well. Possibly because

stopping potential, eVo = KEmax = hf - Wo

and since Wo is dependant on the intensity of light, this will in turn affect our stopping potential. I might be wrong so...yeah..

 

[krytek]

Sorry to wake up the dead.
Stumbled upon this and it looked interesting.

When an electron is hit by a photon which has an energy below the work function, the electron is excited for a short period of time before returning to the initial state. So if the intensity of light is high it is possible for 2 or more photons to hit the same electron (albeit under very low probability) within this very short period of time, thus causing it to detach.

I think this may be a possible explanation.

*edit* Just to clarify, intensity of light is the amount of photons.