What Is the Required Power for a Cable Car on a Slope?

  • Thread starter Thread starter scan
  • Start date Start date
  • Tags Tags
    Physics Power
AI Thread Summary
To determine the required power for a cable car on a slope, first calculate the change in height, which is essential for understanding energy changes. The cable car, moving up a 1000 m slope at a 30-degree angle and a speed of 3.5 m/s, carries 20 persons with an average weight of 600 N each. Work is needed to lift the cable car, and this can be calculated using the height change and the total weight. The time taken to ascend the slope can be derived from the speed and distance, allowing for the calculation of power using the formula Power = Work/Time. Overall, the problem emphasizes the relationship between work, energy changes, and the required power for the cable car operation.
scan
Messages
23
Reaction score
0
A cable car is operated on a slope 1000 m long making an angle of 30deg. with the horizontal. The cable car moves up the slope with a speed of 3.5 m/s and carries 20 persons of average weight 600 N. What power is needed?
 
Physics news on Phys.org
first of all

SHOW US YOU ACTUALLY TRIED TO SOLVE THIS!

secondly draw a free body diagram

what is the change is height of the cable car ? If there is a change in height what else can change (in energy terms)

In order to take something up a height what is needed? To bring about the change in energy we need work.

Figure out the time needed for the cable car to go up that incline.

Now you have work and time thus you have power
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Problem with the power of car
Replies
3
Views
802
CO2-powered metric racer car competition | help please?
Replies
14
Views
1K
Cable car with 2 cable arrangement
Replies
1
Views
7K
Finding the tension of two cables holding an object at rest
Replies
7
Views
2K
Skiing Up a Slope: Solving Work & Power Requirements
Replies
9
Views
2K
How Do You Calculate Race Car Acceleration and Power Output?
Replies
20
Views
2K
Solving a Railway Power Problem: 87.1 kW
Replies
5
Views
2K
Finding friction and tension for a train
Replies
1
Views
2K
Worksheet Problem about Power (average power of a car accelerating up a hill)
Replies
2
Views
2K
Power & Energy Homework: Ore Car Mass 950 kg, Accelerate to 2.2 m/s in 12s
Replies
5
Views
3K

Hot Threads

Recent Insights

Back
Top