What is the resonance frequency expression for a parallel RLC circuit?

AI Thread Summary
The resonance frequency expression for a parallel RLC circuit differs from that of a series RLC circuit, although they can converge under certain conditions. In a series circuit, the resonance frequency is given by w = 1/√(LC), while for a parallel circuit, the relationship involves the admittance of the components. The discussion highlights that both circuits can exhibit similar behavior when the resistance approaches zero in series or infinity in parallel. The resonance condition for the parallel circuit can be expressed as w²LC = r1/r2, where r1 and r2 are the resistances of the components. Overall, while there are similarities, the resonance expressions are not identical in all scenarios.
yxgao
Messages
122
Reaction score
0
What is the resonance frequency expression for a parallel RLC circuit?

I know that for a series RLC circuit, it is:
<br /> w=\frac{1}{\sqrt{LC}}<br />

Is it the same for a parallel RLC circuit? I remember reading somewhere that it was not exactly the same, although it approaches the series RLC expression in a certain limit. What is this limit?

Thanks!
YG
 
Physics news on Phys.org
In general it will be precisely the same because in both instances the reactances of the L and the C must cancel -- in the series circuit jwL + 1/(jwC) = 0
( sum of reactive impedances )
in the parallel circuit 1/(jwL) + jwC = 1/infinity = 0 ( sum of admittances )
they result in the same thing.
If for an instant you put R=0 (series ), or r=infin ( parallel ) then you can see that such a circuit is BOTH series and parallel.
My guess is that Integral got out the wrong side of the bed this morning, but has invested in Google.
Ray.
 
It shouldn't be the same, I don't think. If you read through the site Integral provided, it gives the form for the parallel circuit, which is slightly different, right?
 
For the circuit given with individual component resistances ( I was thinking of a simpler circuit) there is difference depending on your view. The circuit is both series and parallel at the same time ( the source impedance is infinite ). The impedance is minimal and of zero rectance as per your equation looking around the series loop.
However from the source viewpoint that is not the case except for r's very small
The expression for resonance ( meaning infinite parallel reactance is
w^2 .L . C = r1/r2 so if r1=r2 the equation is the same.
Ps I may have the r1,r2 reversed but you get the idea.
Ray
 
Final answer

attached is the simple analysis showing the error or ratio of resonances.
Ray
 

Attachments

  • SerPar.jpg
    SerPar.jpg
    17 KB · Views: 636
Thanks! I really appreciate it!




\lambda



\mu
 

Similar threads

Replies
22
Views
2K
Replies
21
Views
1K
Replies
40
Views
5K
Replies
32
Views
2K
Replies
3
Views
2K
Replies
5
Views
3K
Back
Top