What is the result of mixing 10g of ice at -10 deg celcius?

  • Thread starter Thread starter postthreads
  • Start date Start date
  • Tags Tags
    Explanation
AI Thread Summary
Mixing 10g of ice at -10 degrees Celsius with water will result in the ice absorbing heat until it reaches 0 degrees Celsius, where it will start melting. The specific heat capacity of ice is 2.1 J/g K, and the latent heat of fusion is 336 J/g, which will affect the total energy calculations. The discussion highlights the need for additional information, such as the amount and temperature of the water being mixed with the ice, to fully solve the problem. Without this data, the outcome remains incomplete. The final temperature of the mixture will stabilize at 0 degrees Celsius once the ice has melted.
postthreads
Messages
2
Reaction score
0

Homework Statement


Find the result of mixing 10g of ice at -10 deg celcius. Specific heat capacity of ice = 2.1 J/g K. Specific heat capacity of water is 4.2 J/g K. Specific latent heat of ice = 336 J/g.


Homework Equations





The Attempt at a Solution



0.625g, temperature will remain at 0 deg celcius.
 
Physics news on Phys.org
Your problem statement is incomplete. Mixing 10g of ice with what?
 
mixing with water
 
OK. How much water? Is this going to be a Twenty Questions session?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Mixing water and ice
Replies
12
Views
867
I try to solve a thermodynamics problem on heat transfer
Replies
3
Views
2K
Calculating Equilibrium Temperature of Ice and Water Mixture
Replies
1
Views
2K
What is the Time Required to Boil Away 1.0kg of Ice Using 900W of Power?
Replies
3
Views
1K
Heat question -- Ice cube in a cup of water....
Replies
7
Views
9K
What is the Entropy Change When Water Freezes to Ice?
Replies
4
Views
1K
Final temperature of ice mixed with water
Replies
9
Views
4K
Solving 0.02 kg Ice and 0.10 kg Water at 0°C to Melted State
Replies
8
Views
3K
A wet cloth has been hung out to dry....
Replies
3
Views
2K
Mass of Ice required to achieve a certain final Temperature
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top