What is the rocket's initial acceleration?

AI Thread Summary
To find the rocket's initial acceleration, the discussion emphasizes using the conservation of momentum rather than relying solely on the rocket equation. The rocket ejects 1/120 of its mass at a relative speed of 2400 m/s in the first second of firing. The instantaneous mass flow rate is calculated as -Mi/120 kg/s, leading to the formula for acceleration a = -Ve/Me × dM/dt. The calculations yield an initial acceleration of 20 m/s², assuming the mass loss is negligible over the first second. Understanding the mass flow rate and its implications is crucial for solving the problem accurately.
JoeDGreat
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Homework Statement
A rocket is in outer space, far from any planet, when the rocket engine is turned on. In the first second of firing, the rocket ejects 1/120 of its mass with a relative speed of 2400m/s. What is the rocket's initial acceleration?
Relevant Equations
Vf-Vi = VeIn(Mi/Mf)
Help me solve... I'm getting errors here..
 
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The rocket equation you have quoted is not very useful to find acceleration. For that you need to look at the fundamental conservation law that is behind the rocket equation, and specifically how the conserved quantities of the rocket and ejected propellant change the instant the rocket is turned on.
 
JoeDGreat said:
Homework Statement: A rocket is in outer space, far from any planet, when the rocket engine is turned on. In the first second of firing, the rocket ejects 1/120 of its mass with a relative speed of 2400m/s. What is the rocket's initial acceleration?
Relevant Equations: Vf-Vi = VeIn(Mi/Mf)

Help me solve... I'm getting errors here..
Per forum rules, please post your attempt.
 
a = -Ve/Me × dM/dt
dM/dt = Mi/120 ÷ 1sec = -Mi/120sec
a =-2400/Mi ( -Mi/120) = 20m/s²

PS: This is the textbook solving but, I don't know how dM= Mi/120
 
JoeDGreat said:
a = -Ve/Me × dM/dt
dM/dt = Mi/120 ÷ 1sec = -Mi/120sec
a =-2400/Mi ( -Mi/120) = 20m/s²

PS: This is the textbook solving but, I don't know how dM= Mi/120
They are giving you the instantaneous rate of mass ejection at ##t=0##:

## \dot M(0) = -\frac{1}{120}M \frac{ \text{kg}}{ \text{s}} ##

Then apply "The Rocket Equation" at ##t = 0## (with no external forces).
 
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JoeDGreat said:
In the first second of firing, the rocket ejects 1/120 of its mass with a relative speed of 2400m/s.
Is it this statement that is giving you interpretive issues? They should have just said something to the effect of " at the instant of firing", or we are just to assume the mass flow rate as constant over the first second for the sake of simplicity (i.e. being able to find a solution).
 
A loss of 1/120th of total mass is sufficiently small that we don't need to worry about how it changes over the second, or, indeed, that it changes at all. Just use momentum conservation: m/120 * 2400m/s = m*v.
Then a=v/t.
 
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