What is the smallest horizontal force needed to move the crate upward?

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The discussion centers on calculating the smallest horizontal force needed to move a crate upward while it is held against a wedge by a spring. The crate's parameters include a spring constant of 1650 N/m, a mass of 22.0 kg, and a static friction coefficient of 0.150. Initial calculations yielded a force of 141 N, which was deemed incorrect, prompting further analysis. A key oversight identified was the neglect of the static friction force acting on the crate, which significantly impacts the calculations. The conversation concludes with a suggestion to consult a professor for clarification on the correct approach.
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Homework Statement


The crate shown is held against wedge B by a spring. The spring is 96.0% of its original uncompressed lengthl=2.75m, and the spring constant is given ask=1650N/m. The coefficient of static friction at all contacting surfaces is μs=0.150. The mass of the crate is m=22.0kg . The angle is θ=11.0∘. Neglect the mass of the wedge. Assume the crate only moves in the y direction and that wedge A cannot move.
8.3_main.jpg

Determine the magnitude of the smallest horizontal force P that is necessary to begin moving the crate upward.

Homework Equations

The Attempt at a Solution


I found the normal from the spring and the weight of the box to be 397N (this is known to be the correct value).

Since A can't move, we can draw a FBD of block B.

Untitled.png

I noticed that I drew the line for the 79 degree angle for f wrong. ignore it. The 79 degrees is supposed to be along the Y-axis. The number is still correct.

Sum of the forces in X = 0 = -P + Ncos79 + .15Nsin79

Sum of the forces in Y=0=-397+NSin79 - .15Ncos79

Using a matrix to solve for P we get P=141 N which is incorrect. I've ran out of ideas here. Every way I do it I seem to get the same answer but it supposedly incorrect.
 
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You have substituted your integer answer into the equations and confirmed it's a perfect fit?

Do you know what the correct answer is supposed to be?

I make the spring & weight combo to be 397.1N (using g=9.8 m/s²).
 
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Yes. It's close enough. The answer doesn't need to be exact. It's 3 sig-figs and within 5 or 10 % and the program will let you know the answer.
 
My working agrees with your pair of ∑ f[/size] equations.
 
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Very strange... I will ask my professor tomorrow. Thank you, Sir.
 
You forgot the force of static friction between the crate and block B, opposing block B moving to the left (it points to the right at the top of the block). When you sum forces in the x this will change your answer slightly for F which actually changes a lot in your answer. Hope this helps anyone else who is looking to this for help!
 
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