What is the Solution for Trig Homework Question?

  • Thread starter Thread starter Anonymous™
  • Start date Start date
  • Tags Tags
    Homework Trig
AI Thread Summary
The discussion revolves around solving two trigonometric equations: cot Θ + tan Θ = csc^2 Θ + sec^2 Θ and 1 - 2 cos Θ = tan Θ - cot Θ. Forum members emphasize the importance of showing work before receiving help, adhering to forum rules. They suggest using LaTeX for clarity, though it's not mandatory, and recommend rewriting equations in terms of sine and cosine for easier manipulation. The conversation highlights a collaborative approach to problem-solving, encouraging users to engage actively with their homework.
Anonymous™
Messages
3
Reaction score
0
1.)/// cot Θ + tan Θ = csc^2 Θ + sec^2 Θ
//////////////////////// -------------------
/////////////////////////// csc Θ sec Θ


2.)/// 1-2 cos Θ = tan Θ - cot Θ
////// -----------
////// sin Θ cos Θ


I also need to know how to get the solution to prove this. Thanks in advance!
:smile:
 
Last edited:
Physics news on Phys.org
1. Please do not hijack another persons thread, instead start a new one.

2. We need to see some working on your part, we don't do your homework for you.

3. What are all those slashes for? Learn LaTeX please.
 
Right.

Never mind then.
 
Whilst what Gib Z said regarding the need for you to show your work before you obtain help here is true (these are forum rules), it is not strictly necessary for you to learn LaTex. It is quite straightforward (click on the \Sigma button on the top of the reply window) but it would be sufficient for you to write equations in the forum: however, instead of using slashes to space the maths, use brackets-- e.g. (sinx+cosx)/(secx).

As for your questions, what are you doing-- proving that they are equalities? Well, I would start off by writing everything in terms of sine and cosine, then looking for possible places to cancel. If you want to have a go, then post back, we will be happy to advise.

Edit: Actually, for the first one, split the right hand side up into two fractions, and cancel-- you don't need to change into sine and cosines on this occasion.
 
Last edited:
Thank you cristo.

But I'm afraid to ask again, so I think I'm going to look for help elswhere.

Peace!
 
Lol I think I scared off a member >.< my bad..
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top