What is the Solution to the Retarding Force Problem?

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Homework Help Overview

The problem involves a particle moving in a medium under the influence of a retarding force defined as mk(v^3 + va^2), where k and a are constants. The goal is to demonstrate that the particle will not exceed a certain distance and will come to rest as time approaches infinity.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss integrating the retarding force to solve for velocity and position, with attempts to apply trigonometric substitution. Questions arise regarding the validity of the results and the handling of imaginary numbers in the solutions.

Discussion Status

There is an ongoing exploration of the integration process and the implications of the results obtained. Some participants have confirmed their understanding of the equations derived, while others are questioning the correctness of their approaches and the physical concepts involved.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can use. The discussion reflects uncertainty regarding the integration steps and the interpretation of the results.

skeer
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The Problem:
A particle moves in a medium influenced by a retarding force mk(v^3+va^2), where k and a are constants.
Show that
for any initial velocity the particle will never move more than (pi)/(2ka)
and
that it comes to rest only for t -> infinity

Attempt to solution:

I know I have to integrate the retarding force [F=-mk(v^3+va^2))] so that I can solve for v. Later, I have to solve for the constant C of the indefinite integral. Afterwards, I have to integrate to find the position.

To show the first part, I believe I have to find the value of the position as t-> infinity.
To show the second part, I believe I have to find the value of the velocity as t->infinity.

My problem: I cannot solve for v

I have solved the integral of the retarding force using trig substitution (v=acot(theta)) (dv=-acsc^2(theta)d(theta))
My final answer is:

t=(-1/ka^2)(ln(v/(sqrt(v^2+a^2))+C

If I use the quadratic equation to solve for v, I get imaginary numbers...
Am I making a mistake in my calculus or algebra?
or
Am I missing a physical concept?
 
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Draw a free body diagram for the particle in motion.
Apply ##F=m\dot v##.
 
After the free body diagram this is what I obtained.
Since the only force acting on it is the retarding force, it equals: F= -mk(v^3+va^2) = m(dv/dt)
This is a velocity dependent force. Therefore, I integrated the force as dt = -dv/(k(v^3+va^2)
then, I used trig substitution for v = acot(x) and dv=-csc^2(x)
And after integrating I obtain:

t= (-1/ka2)(ln(v/(sqrt(v^2 +a^2)) + C

Is this correct so far?
 
skeer said:
After the free body diagram this is what I obtained.
Since the only force acting on it is the retarding force, it equals: F= -mk(v^3+va^2) = m(dv/dt)
This is a velocity dependent force. Therefore, I integrated the force as dt = -dv/(k(v^3+va^2)
then, I used trig substitution for v = acot(x) and dv=-csc^2(x)
And after integrating I obtain:

t= (-1/ka2)(ln(v/(sqrt(v^2 +a^2)) + C

Is this correct so far?
Have you checked that by differentiating to get the ODE?
 
haruspex said:
Have you checked that by differentiating to get the ODE?
Yes, I checked. I realize also what was my problem. Thank you all
 

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