What is the speed of sound in air at atmospherical conditions?

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Homework Help Overview

The discussion revolves around calculating the speed of sound in air based on an echo heard after a clap, with specific measurements provided for distance and time. The subject area is primarily related to kinematics and acoustics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial calculation of speed using the formula V=d/t, questioning the correctness of the distance used in the calculation. There is an exploration of whether the distance should account for the echo's return journey.

Discussion Status

Some participants have provided guidance on the calculation, noting the need to consider the total distance for the echo. Multiple interpretations of the problem are being explored, particularly regarding the distance the sound travels.

Contextual Notes

Participants are working under the assumption that the echo reflects off a cliff, which affects the total distance sound travels. There is also a reference to typical values for the speed of sound in air under atmospheric conditions.

Sace Ver
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Homework Statement


A student stands 86m from the foot of a cliff, claps her hands, and hears the echo 0.50s later. Calculate speed of sound in air.

Known
•86m
•0.50s

Homework Equations


V=331.4+0.606T

The Attempt at a Solution


V=d/t
V=86m/0.50s
V=172m/s

Is that the first step to the problem? If so I'm not quite sure what the next step is.
 
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Sace Ver said:

Homework Statement


A student stands 86m from the foot of a cliff, claps her hands, and hears the echo 0.50s later. Calculate speed of sound in air.

Known
•86m
•0.50s

Homework Equations


V=331.4+0.606T

The Attempt at a Solution


V=d/t
V=86m/0.50s
V=172m/s

Is that the first step to the problem? If so I'm not quite sure what the next step is.
What is the total distance the sound has to travel between the moment she claps her hand and the moment she hears the echo?
 
Sace Ver said:

The Attempt at a Solution


V=d/t
V=86m/0.50s
V=172m/s

Your formula is correct, but the value of the distance you used isn't.
 
stockzahn said:
Your formula is correct, but the value of the distance you used isn't.
86m x 2 = 172 bc it is an echo?

V=d/t
V=172m/0.50s
V=344m/s
 
That seems to be correct - about 340 m/s is a typical value for the speed of sound of air at atmospherical conditions. I also think that this is the only step of the calculation (at least according to the statement).
 

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