What is the speed of the particle after 9:01 s?

  • Thread starter NINHARDCOREFAN
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In summary, a particle with an initial velocity of 20.7 m/s in the x direction and -16.3 m/s in the y direction has an x-component acceleration of 5.03 m/s2. After 9.01 seconds, the x-component of velocity is 65.8 m/s and the speed of the particle is 82.32 m/s. To find the displacement after 9.01 seconds, use the Pythagorean theorem to calculate the length of the vector formed by the x and y components of velocity.
  • #1
NINHARDCOREFAN
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A particle starts from the origin at t = 0 with an initial velocity having an x component of 20:7 m/s and a y component of -16:3 m/s. The particle moves in the xy plane with an x component of acceleration only, given by 5:03 m/s2.
A)Determine the x component of velocity after 9:01 s. Answer in units of m/s.

B)Find the speed of the particle after 9:01 s.
Answer in units of m/s.

I have found the answer to A as 66.02 but for B isn't the answer 66.02-(-16.32)= 82.32?
 
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  • #2
The point of the first part of the problem is that you can do the x and y components separately.

Since the x-component of velocity is initially 20.7 m/s and there is an acceleration of 5.03 m/s2, the x-component of velocity at any time t is given by 20.7+ 5.03t. When t= 9.02, this is 20.7+ 5.03*9.01= 65.8 m/s.
That's not quite what you got. Is your "20:7" something other than "20.7"??

More importantly, you cannot add components like you do for B.
Set up a right triangle with x-component as one leg and y-component as the other. The "speed" is the length of the vector itself- the hypotenuse of your right triangle. Use the Pythagorean theorem to calculate that.
 
  • #3
"never mind I figured that out, but how do I find the displacement after 9.01s?(in the previous post colon was supposed to be a dot sign(:=.)"

should have read my other thread
 
  • #4
Just as I said: after you have found the "x-component" and the "y-component" you know the legs of a right triangle having the vector itself as hypotenuse. Use the Pythagorean theorem to find the length of that vector. That's the "displacement".
 

What is speed in a 2D problem?

Speed in a 2D problem refers to the rate at which an object moves in a two-dimensional space, often measured in distance traveled per unit of time.

How is speed calculated in a 2D problem?

Speed in a 2D problem can be calculated by dividing the distance traveled by the time it took to cover that distance. The formula for speed is: speed = distance / time.

What are the units of measurement for speed in a 2D problem?

The units of measurement for speed in a 2D problem can vary, but some common units include meters per second (m/s), kilometers per hour (km/h), and miles per hour (mph).

How is speed related to velocity in a 2D problem?

Speed and velocity are often used interchangeably, but in a 2D problem, they have different meanings. Speed is a scalar quantity that only takes into account the magnitude of an object's movement, while velocity is a vector quantity that includes both the magnitude and direction of an object's movement.

How can speed affect the outcome of a 2D problem?

Speed can greatly impact the outcome of a 2D problem, as it affects how quickly an object moves and covers a certain distance. It can also affect other quantities such as acceleration and force, which can in turn affect the overall outcome of the problem.

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