What is the speed of the sports car at the second marker?

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The sports car accelerates at 1.8 m/s² and covers a distance of 120 meters in 4.1 seconds. Initial velocity (vi) was calculated to be 14.2 m/s. Using the average velocity formula, the final velocity (vf) was found to be 25.2 m/s. However, there is a suggestion that the calculations may contain errors, prompting a review of the numbers. Accurate calculations are crucial for determining the car's speed at the second marker.
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A sports car, picking up speed, passes between two markers in a time of 4.1s. The markers are separated by 120m. All the while, the car accelerates at 1.8m/s^2. What is its speed at the second marker?

Here is what i did:

d = vi(t)+1/2(a)t^2
120=vi(4.1)+1/2(1.8)(4.1)^2
29.3=vi+15.1
vi=14.2m/s

d=1/2(vi+vf)t
120=1/2(14.2+vf)(4.1)
vf=44.3m/s
vf=25.2m/s
 
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miamiheat5 said:
A sports car, picking up speed, passes between two markers in a time of 4.1s. The markers are separated by 120m. All the while, the car accelerates at 1.8m/s^2. What is its speed at the second marker?

Here is what i did:

d = vi(t)+1/2(a)t^2
120=vi(4.1)+1/2(1.8)(4.1)^2
29.3=vi+15.1
vi=14.2m/s

d=1/2(vi+vf)t
120=1/2(14.2+vf)(4.1)
vf=44.3m/s
vf=25.2m/s

Your calculation is wrong. Check the numbers once again.
 
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