What is the Spring Constant of a Spider's Silk Thread?

[brunettegurl]

Homework Statement

A 2.60 g spider is dangling at the end of a silk thread. You can make the spider bounce up and down on the thread by tapping lightly on his feet with a pencil. You soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap exactly once every 4.90 s seconds. What is the spring constant of the silk thread.

Homework Equations

\omega= 2\pi/T
\omega= \sqrt{}k/m

The Attempt at a Solution

so i equated the 2 equations and tried to isolate for k and this is what my equation looked like : m*(2\pi/T)^2 = k ..i tried rearranging twice and my answer and equation are coming out the same ..pls. help

 

[Doc Al]

so i equated the 2 equations and tried to isolate for k and this is what my equation looked like : m*(2\pi/T)^2 = k ..i tried rearranging twice and my answer and equation are coming out the same ..pls. help

That looks fine to me. Why do you think it's not?

 

[brunettegurl]

when i put the answer into my hwk the answer is appparently wrong..i was also wondering if i was right in assuming the period to be 4.90 seconds??

 

[nrqed]

Homework Statement

A 2.60 g spider is dangling at the end of a silk thread. You can make the spider bounce up and down on the thread by tapping lightly on his feet with a pencil. You soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap exactly once every 4.90 s seconds. What is the spring constant of the silk thread.

Homework Equations

\omega= 2\pi/T
\omega= \sqrt{}k/m

The Attempt at a Solution

so i equated the 2 equations and tried to isolate for k and this is what my equation looked like : m*(2\pi/T)^2 = k ..i tried rearranging twice and my answer and equation are coming out the same ..pls. help

What value did you get ? Did you convert the mass to kg ? (I assume they want the k in N/m)

 

[brunettegurl]

the value i am getting is 4.85x10^-3 N/m

 

[Doc Al]

i was also wondering if i was right in assuming the period to be 4.90 seconds??

Yes, that was correct.

 

[Doc Al]

the value i am getting is 4.85x10^-3 N/m

Double check your arithmetic.

 

[brunettegurl]

thankx i got it