What is the strength of the magnetic field

AI Thread Summary
To determine the strength of the magnetic field in an AC generator with a circular coil of 49 turns and a radius of 3.1 cm, the amplitude of the emf is given as 17.0 V and the armature rotates at 382 rpm. The user calculated the magnetic flux (phi) as 18.35 Webers but needs to convert this value to Tesla. The conversion requires understanding that 1 Tesla equals 1 Weber per square meter. The discussion emphasizes the importance of mastering electric units for accurate calculations.
warrior2014
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Homework Statement



The armature of an ac generator is a circular coil with 49 turns and radius 3.1 cm. When the armature rotates at 382rpm, the amplitude of the emf in the coil is 17.0 V. What is the strength of the magnetic field (assumed to be uniform) ?

Homework Equations


E = N.n.phi


The Attempt at a Solution


I solved for phi and got 18.35 (Webers) Wb. But, I need the answer in Tesla (T) and I am unsure how to do this. Please help!
 
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A Weber is a unit of flux whereas a Tesla is a unit of flux density
 
hi warrior2014! :smile:
warrior2014 said:
I solved for phi and got 18.35 (Webers) Wb. But, I need the answer in Tesla (T) and I am unsure how to do this. Please help!

hint: learn your electric units …

1 T = 1 Wb/m2 :wink:​
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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