What is the Susceptibility of a Linear Dielectric Material?

jackxxny
Messages
39
Reaction score
0

Homework Statement


I have a linear dielectric material. The electric field in the material is 38% less than a vacuum field with the same external sources. I need to find the susceptibility of the material?

Homework Equations



I used
P=\epsilon\chi(vacuum)E
P=\epsilon\chi(material).62E

The Attempt at a Solution


i did the ratio of the 2 and i found

\chi(material)= 1.61

is this correct?
 
Physics news on Phys.org
jackxxny said:
i did the ratio of the 2 and i found

\chi(material)= 1.61

is this correct?

I'm not sure what you mean here.. the polarization in vacuum should be zero shouldn't it? What field stays the same when the free charge sources are unchanged? Electric field ? Displacement field? Polarization?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top