What is the tangential acceleration of a flywheel particle during deceleration?

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SUMMARY

The discussion focuses on calculating the tangential acceleration of a flywheel particle during deceleration. The flywheel operates at a constant angular speed of 375 revolutions per minute (rev/min) and experiences an angular acceleration of -3.47 rev/min². At the moment the flywheel is at 75 rev/min, the tangential component of linear acceleration for a particle located 50 cm from the axis of rotation is derived using the formula: tangential acceleration = (angular acceleration) × (radius). The correct conversion of units from rev/min² to rad/s² is essential for accurate calculations.

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Homework Statement



The flywheel of a steam engine runs with a constant angular speed of 375 rev/min. When steam is shut off, the friction of the bearings stops the wheel in 1.8 h.

At the instant the flywheel is turning at 75 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 50 cm from the axis of rotation?

Angular Acceleration: -3.47 rev/(min^2)


Homework Equations



Tangential component of the linear acceleration = (angular acceleration)(radius to object)

The Attempt at a Solution



I tried dividing the angular acceleration figure by 60 to make it in rev/(sec^2), then multiplied by r (.5 m), and ended up with the wrong answer. I tried multiplying that angular acceleration figure by 2pi to convert it to radians then multiplied it out, but still no dice. I have one attempt left. Do I need to clarify anything?
 
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The units are rev/min2. 1 revolution is 2π rad and 1min2 is 3600s2, so you need to multiply rev/min2 by 2π/3600 to get it into rad/s2
 
ah, so I was close. thanks.
 

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