What is the tangential acceleration of a flywheel particle during deceleration?

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The discussion revolves around calculating the tangential component of linear acceleration for a flywheel particle during deceleration. The flywheel operates at a constant angular speed of 375 rev/min and decelerates to 75 rev/min over 1.8 hours, with an angular acceleration of -3.47 rev/(min^2). To find the tangential acceleration, the angular acceleration must be converted to radians per second squared by using the conversion factor of 2π/3600. The user initially struggled with unit conversions and calculations but is close to the correct approach. Clarification on the conversion process was provided, emphasizing the importance of accurate unit transformation.
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Homework Statement



The flywheel of a steam engine runs with a constant angular speed of 375 rev/min. When steam is shut off, the friction of the bearings stops the wheel in 1.8 h.

At the instant the flywheel is turning at 75 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 50 cm from the axis of rotation?

Angular Acceleration: -3.47 rev/(min^2)


Homework Equations



Tangential component of the linear acceleration = (angular acceleration)(radius to object)

The Attempt at a Solution



I tried dividing the angular acceleration figure by 60 to make it in rev/(sec^2), then multiplied by r (.5 m), and ended up with the wrong answer. I tried multiplying that angular acceleration figure by 2pi to convert it to radians then multiplied it out, but still no dice. I have one attempt left. Do I need to clarify anything?
 
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The units are rev/min2. 1 revolution is 2π rad and 1min2 is 3600s2, so you need to multiply rev/min2 by 2π/3600 to get it into rad/s2
 
ah, so I was close. thanks.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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