What is the temperature of the bath?

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The discussion centers on calculating the temperature of a liquid bath using the resistance of a gold wire. At 50 degrees Celsius, the wire's resistance is 54 ohms, which increases to 189 ohms in the bath. The temperature coefficient of resistivity is given as 0.0034 (°C)^-1 at 20 degrees Celsius. One participant applies the formula p-po = (po)a(T-To) but arrives at an implausibly high temperature of 785.29 degrees Celsius, suggesting a possible error in calculation. The conversation highlights the complexity of the calculation and the need for careful verification of results.
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At 50 degrees Celsius, the resistance of a segment of gold wire is 54. When the wire is placed in a liquid bath, the resistance increases to 189. The temperature coefficient is 0.0034 (degrees Celsius)^-1 at 20 degrees Celsius.
What is the temperature of the bath? Answer in units of degrees Celsius.
 
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What have you done so far?
 
I tried to use the equation:
p-po = (po)a(T-To)
To= reference temperature
po= resistivity at that temperature
a= temperature coefficient of resistivity

So I did:
189-54 = (54)(0.0034)(T-50)

But I know the answer I got that way is wrong.
 
It sure looks to me like you've got the right equation. Are you sure you solved it correctly?

The form of the equation that I am familiar with is

R = \alpha T

where T is given in degrees Kelvin. But this reduces to your form in either degrees K or degrees C (or F).

Carl
 
When I use the formula I mentioned above, I get T=785.29 degrees Celsius. I don't know if I solved it incorrectly but I did:
189-54=(54)(0.0034)(T-50)
135=(0.1836)(T-50)
735.29=T-50
T= 785.29
 
Sure looks right to me. But that's a mighty hot bath. Maybe a molten salt bath.

Carl
 
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