What is the tension in the cylindrical wire?

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SUMMARY

The tension in a cylindrical wire over a frictionless pulley can be calculated using Newton's second law. In this scenario, a 5.8 kg mass and a 1.5 kg mass are connected by a massless wire. The gravitational acceleration is given as 9.8 m/s². By applying Newton's second law to both masses, the tension in the wire can be determined as uniform due to the massless nature of the wire.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Knowledge of free body diagrams
  • Familiarity with concepts of tension in strings and pulleys
  • Basic grasp of gravitational acceleration (g = 9.8 m/s²)
NEXT STEPS
  • Calculate the tension in the wire using the formula T = (m1 * g - m2 * g) / (m1 + m2)
  • Explore the effects of adding mass to the wire and how it alters tension
  • Investigate the dynamics of non-frictionless pulleys and their impact on tension
  • Learn about the applications of tension in various mechanical systems
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the principles of tension in pulleys and wires.

directdelta
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A cylindrical wire is placed over a frictionless pulley with one end of a wire connected to a 5.8 kg mass and the other to a 1.5 kg mass. If g=9.8 m/s/s, what is the tension in the wire?


I have no idea how to start on this.
 
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Since it is not stated otherwise, assume the wire is massless. Draw a free body diagram for each mass and apply Newtons 2nd law to each of them. The tension in the wire will be uniform (massless wire) and the masses will have common magnitudes of displacement, velocity, and acceleration.
 

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