What is the tension in the string for two blocks on a spinning turntable?

  • Thread starter Thread starter rgalvan2
  • Start date Start date
  • Tags Tags
    Blocks Turntable
AI Thread Summary
The discussion revolves around calculating the tension in a string connecting two blocks on a spinning turntable. The inner block is positioned 4 cm from the center, while the outer block is 5 cm away, with a static friction coefficient of 0.74. The maximum angular frequency calculated was 12.7 rad/s, ensuring neither block slides. The tension in the string was initially miscalculated, but after converting mass from grams to kilograms, the correct value was determined. The conversation highlights the importance of unit conversion and proper application of physics equations in solving the problem.
rgalvan2
Messages
26
Reaction score
0
Two identical blocks are tied together with a string and placed along the same radius of a turntable that is spinning about its center. The inner block is 4 cm from the center and the outer block is 5 cm from the center. The coefficient of static friction between the turntable and the blocks is µs = 0.74, and the string is taut.

a) What is the maximum angular frequency such that neither block slides?
I got w= 12.7 which was right

b) Now suppose that the blocks each have a mass m = 21 g. For the value of w you just found, what is the tension in the string?
T= ?N

I am stuck on b) I have 2 eqns:
T+\mumg=mR1w^2
-T+\mumg=mR2w^2

So I keep getting 17N each time I try. What am i doing wrong?
T=mR1w^2-\mumg
=21x.05x12.7^2 - .74x21x9.81
=169.4-152.4= 17N

Help Please!
 
Physics news on Phys.org
I can't help you dude. I need help with the same problem. All I can figure out is that the net force points to the center of the circle I believe, and https://www.physicsforums.com/latex_images/18/1883140-2.png probably doesn't point toward the center, I think.

I'm still stuck on A and have no idea how to procede.
If you finish the problem, and if you have some extra time could you help me with it please? :)
 
Last edited by a moderator:
did u convert grams to kg?
 
I was actually just doing that as when i saw i got a new reply. I thought i tried that before but i must have miscalculated. i got it right now thanks!
 
haha yeah, i just solved it thanks to some help from someone else. peace. :)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top