What is the Torque on a Hinged Door with a 30 N Force at 1.5 m Distance?

  • Thread starter Thread starter erinbrattin
  • Start date Start date
  • Tags Tags
    Torque
AI Thread Summary
A force of 30 N is applied perpendicularly to a hinged door at a distance of 1.5 m from the hinge. The torque on the door can be calculated using the formula: torque equals force multiplied by the perpendicular distance from the hinge. In this case, the torque is 30 N multiplied by 1.5 m, resulting in a torque of 45 N·m. This calculation illustrates how torque is directly influenced by both the magnitude of the force and the distance from the pivot point. Understanding this concept is essential for analyzing the mechanics of hinged doors.
erinbrattin
Messages
5
Reaction score
0
a force of 30 n is applied perpeddicularly to the face of a hinge door at a distance of 1.5 m from the hinge of the door. find the torque on the door about it's hinge
 
Physics news on Phys.org
The torque created about an axle or a ploint is the force times the perpendicular distance from the axle to the point of force.

Regards,

Nenad
 
thank you!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top