What is the total capacitance for the RC circuit lab problem with given data?

AI Thread Summary
To find the total capacitance for the RC circuit, the individual capacitances C1 and C2 must be calculated using the half-life data and the given resistance. C1 is determined to be approximately 34.6 µF, while C2 is about 17.3 µF. For capacitors in series, the total capacitance is found using the formula 1/C_total = 1/C1 + 1/C2, and for capacitors in parallel, the total capacitance is C_total = C1 + C2. The discussion emphasizes the correct application of these formulas to arrive at the final total capacitance. Proper calculations will lead to the completion of the lab problem.
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Homework Statement



I did the RC circuit lab
I measure the actual resistance of 1000Ω
Function Generator Resistance: 50 Ω
Function Generator Frequency: 1.4Hz

resistor used was 41uF in C1
Resistor used was 22uf for c2


So i have to find c1, c2 and use c1,c2 to calc. the total capacitance for series/parallel

Data:
Half Life:
C1: 1.200 milli sec
C2: 0.600 milli sec
Series C1, C2: 1.400 millisec
Parallel C1,C2: 2.000 millisec


Homework Equations




C= (t 1/2)/ Rln2



The Attempt at a Solution



C1: ( 1.200e-3)/ 50Ω * ln2 = 3.46E-5
C2: (.600 e-3)/ 50Ω* ln2= 1.73e-5

for parallel/ series capacitors, I'm not sure where to continue.

is it add up the c1 and c2 and that's my series capacitance? and 1/c1 +1/c2= my parallel capacitance?
 
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Use c = c1+c2 if they are in parallel.
Use 1/c = 1/c1 + 1/c2 if they are in series.
 


once i used my solve individual C's to solve in the series/ parallel then I'm done right?
 
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