What is the unit vector parallel to A at point P(1,-1,2)?

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To find the unit vector parallel to vector A at point P(1,-1,2), first substitute the coordinates into the expression for A, resulting in A = -1i - 5j + 4k. Next, calculate the magnitude of A using the formula Sqrt((-1)² + (-5)² + (4)²), which equals Sqrt(42). Finally, divide each component of A by its magnitude to obtain the unit vector. This process ensures the new vector has a length of one while maintaining its direction.
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How can I calculate the following?
Given A=\hat{x}(x+2y)-\hat{y}(y+3z)+\hat{z}(3x-y)
Determine a unit vector parallel to A at point P(1,-1,2).
 
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It's straight forward substitution. Find the vector A at the given point and then calculate the unit vector by scaling A by the inverse of its length (thus making the new vector's length one).
 
I agree. By substitution A=-1i-5j+4z, The magnitude of A = Sqrt((-1)2+(-5)2+(4)2). Divide the magnitude into A to get the unit vector.
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks
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