What is the upward force on the hot air balloon?

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SUMMARY

The upward force on a hot air balloon can be calculated using Newton's second law, where the net force (Fnet) equals the applied force (Fa) minus the gravitational force (Fg). In the case of the hot air balloon with a mass of 315 kg and a downward acceleration of 1.10 m/s², the upward force is determined to be 3,135 N. To achieve zero acceleration, the balloonist must discard a specific mass of ballast, which can be calculated by adjusting the forces acting on the system.

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  • Understanding of Newton's laws of motion
  • Familiarity with force diagrams (Free Body Diagrams)
  • Basic knowledge of mass, weight, and acceleration
  • Ability to perform calculations involving forces and mass
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  • Study the application of Newton's second law in various contexts
  • Learn how to construct and analyze Free Body Diagrams
  • Explore the concepts of buoyancy and forces in fluid dynamics
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Physics students, educators, and anyone interested in understanding the mechanics of forces and motion, particularly in relation to buoyancy and hot air balloons.

emma3001
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I have 2 problems that i can't do

You apply a force of 0.35N up to lift a fork. The resulting acceleration is 0.15m/s2 up. Determine the mass of the fork (the answer is 35g-why?)

A hot air balloon has acceleration of 1.10m/s2 down. The mass is 315kg.
What is the upward force on the system?
The balloonist wished to change acceleration to zero. Determine the mass of the ballast that must be discarded overboard (air resistance is neglected)

please help!
 
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i thought that Fnet=Fa-Fg=ma so i said that Fa=0.35N and a=0.15m/s2.

Then Fg=mg so 0.35N=m(9.8)
m=0.036kg but the answer is 35g so do u have to subtract 9.8ms2 from the given a?
I drew a FBD but i still am confused as to how to do it.
 
fork problem

emma3001 said:
i thought that Fnet=Fa-Fg=ma so i said that Fa=0.35N and a=0.15m/s2.
This is correct.
Then Fg=mg
Also true. Here's how you combine them:
Fa - Fg = ma
Fa - mg = ma
Fa = mg + ma
Fa = m(g + a)

Continue and solve for m.
 
thank you very much-these concepts are hard to wrap my head around!
 

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